File Upload

Alias: Umbraco.UploadField

Returns: string

Adds an upload field, which allows documents or images to be uploaded to Umbraco.

You can define which file types should be accepted through the upload field.

For uploading and adding files and images to your Umbraco project, we recommend using the Media Picker.

Find the full documentation for the property in the Media Picker article.

Data Type Definition Example

Content Example

In code, the property is a string, which references the location of the file.

Example: "/media/o01axaqu/guidelines-on-remote-working.pdf"

MVC View Example

Without Modelsbuilder

@using System.IO;
@{
    if (Model.HasValue("myFile"))
    {
        var myFile = Model.Value<string>("myFile");

        <a href="@myFile">@System.IO.Path.GetFileName(myFile)</a>
    }

}

With Modelsbuilder

@if (!Model.HasValue(Model.MyFile))
{
   <a href="@Model.MyFile">@System.IO.Path.GetFileName(Model.MyFile)</a>
}

Add values programmatically

The samples in this section have not been verified against the latest version of Umbraco.

Instead, we recommend using the Media Picker for uploading files to your Umbraco website.

See the example below to see how a value can be added or changed programmatically. To update a value of this property editor you need the Content Service and the Media Service.

@using Umbraco.Cms.Core.IO
@using Umbraco.Cms.Core.Serialization
@using Umbraco.Cms.Core.Strings
@inject MediaFileManager _mediaFileManager;
@inject IShortStringHelper _shortStringHelper;
@inject IContentTypeBaseServiceProvider _contentTypeBaseServiceProvider;
@inject IContentService Services;
@inject IJsonSerializer _serializer;
@inject MediaUrlGeneratorCollection _mediaUrlGeneratorCollection;

@{
   // Get access to ContentService
    var contentService = Services;

    // Get access to MediaService 
    var mediaService = MediaService;

    // Create a variable for the GUID of the parent where you want to add a child item
    var guid = Guid.Parse("32e60db4-1283-4caa-9645-f2153f9888ef");

    // Get the page using the GUID you've defined
    var content = contentService.GetById(guid); // ID of your page

    // Create a variable for the file you want to upload, in this case the Our Umbraco logo
    var imageUrl = "https://our.umbraco.com/assets/images/logo.svg";

    // Create a request to get the file
    var request = WebRequest.Create(imageUrl);
    var webResponse = request.GetResponse();
    var responseStream = webResponse.GetResponseStream();

    // Get the file name 
    var lastIndex = imageUrl.LastIndexOf("/", StringComparison.Ordinal) + 1;
    var filename = imageUrl.Substring(lastIndex, imageUrl.Length - lastIndex);

    // Create a media file
    var media = mediaService.CreateMediaWithIdentity("myImage", -1, "File");
    media.SetValue(_mediaFileManager, _mediaUrlGeneratorCollection, _shortStringHelper, _contentTypeBaseServiceProvider, Constants.Conventions.Media.File, filename, responseStream);
    // Save the created media 
    mediaService.Save(media);

    // Get the published version of the media (IPublishedContent)
    var publishedMedia = Umbraco.Media(media.Id);

    // Set the value of the property with alias 'myFile' 
    content.SetValue("myFile", publishedMedia.Url());

    // Save the child item
    contentService.Save(content);
}

Although the use of a GUID is preferable, you can also use the numeric ID to get the page:

@{
    // Get the page using it's id
    var content = contentService.GetById(1234); 
}

If Modelsbuilder is enabled you can get the alias of the desired property without using a magic string:

@inject IPublishedSnapshotAccessor _publishedSnapshotAccessor;
@{
    // Set the value of the property with alias 'myFile'
    content.SetValue(Home.GetModelPropertyType(_publishedSnapshotAccessor, x => x.MyFile).Alias, publishedMedia.Url();
}

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Last updated 4 months ago